PQRSTV is a regular polygon of side 7 cm inscribed in a circle. Find the circumference of the circle PQRSTV.
- A.
56 cm - B.
22 cm - C.
42 cm - D.
44 cm
Correct Answer: Option D
Explanation
Each interior Angle of the polygon = | (n-2) | 180 |
_n |
= | (6-2) | 180 |
_6 |
= 4 x 30
= 120^{o}
i.e ∠PQR = 120^{o} ∴ RQD = ^{120}/_{2} = 60^{o} also
∴ Δ QOR is equilateral Δ ∴ QO = 7cm
∴ PO = QO = RO …… = 7cm radius of the circumference of the circle = 2πr
= 2 x ^{22}/_{7} x ^{7}/_{1}
= 44 cm